In this article, we will discuss the limit point of a sequence. A set of numbers said to be a limit point of a sequence. It has two types of sequences.
1. Arithmetic sequence and
2. Geometric sequence.
Arithmetic sequence means that, the sequence of a numbers such that the difference between two consecutive members of the sequence is a constant. Geometric sequence means that, the sequence of a numbers such that the ratio between two consecutive members of the sequence is a constant. The limit point of a sequence formulas and example problems are given below.
Sequences formulas are given below.
Formula for arithmetic sequence:
nth term of the sequence : an = a1 + (n - 1)d
Series of the sequence: sn = `(n(a_1 + a_n))/2 `
Formula for geometric sequence:
nth term of the sequence: an = a1 * rn-1
Series of the sequence: sn = `(a_1(1-r^n))/(1 - r)`
Example problem 1:
Find the 11th term of the given series 11, 12, 13, 14, 15,......
Solution:
First term of the series, a1 = 11
Difference of two consecutive terms, d = 12 - 11 = 1
n = 11
The formula to find the nth term of an arithmetic series, `a_n = a_1 + (n-1)d`
So, the 11th term of the series 11, 12, 13, 14, 15,... = 11 + (11 - 1) 1
= 11 + 10 * 1
= 11 + 10
After simplify this, we get
= 21
So, the 11th term of the sequence 11, 12, 13, 14, 15,... is 21.
More Example Problems for Limit Point of a Sequence
Example problem 2:
Find out the 5th term of a geometric sequence if a1 = 70 and the common ratio (C.R) r = 2
Solution:
Use the formula `a_n = a_1 * r^(n-1)` that gives the nth term to find `a_5` as follows
`a_5 = a_1 * r^(5-1)`
= 70 * (2)4
= 70 * 16
After simplify this, we get
= 1120.
The 5th term of a geometric sequence is 1120.
The above examples are helpful to study of limit point of a sequence.
1. Arithmetic sequence and
2. Geometric sequence.
Arithmetic sequence means that, the sequence of a numbers such that the difference between two consecutive members of the sequence is a constant. Geometric sequence means that, the sequence of a numbers such that the ratio between two consecutive members of the sequence is a constant. The limit point of a sequence formulas and example problems are given below.
Formulas and Example Problems for Limit Point of a Sequence
Sequences formulas are given below.
Formula for arithmetic sequence:
nth term of the sequence : an = a1 + (n - 1)d
Series of the sequence: sn = `(n(a_1 + a_n))/2 `
Formula for geometric sequence:
nth term of the sequence: an = a1 * rn-1
Series of the sequence: sn = `(a_1(1-r^n))/(1 - r)`
Example problem 1:
Find the 11th term of the given series 11, 12, 13, 14, 15,......
Solution:
First term of the series, a1 = 11
Difference of two consecutive terms, d = 12 - 11 = 1
n = 11
The formula to find the nth term of an arithmetic series, `a_n = a_1 + (n-1)d`
So, the 11th term of the series 11, 12, 13, 14, 15,... = 11 + (11 - 1) 1
= 11 + 10 * 1
= 11 + 10
After simplify this, we get
= 21
So, the 11th term of the sequence 11, 12, 13, 14, 15,... is 21.
More Example Problems for Limit Point of a Sequence
Example problem 2:
Find out the 5th term of a geometric sequence if a1 = 70 and the common ratio (C.R) r = 2
Solution:
Use the formula `a_n = a_1 * r^(n-1)` that gives the nth term to find `a_5` as follows
`a_5 = a_1 * r^(5-1)`
= 70 * (2)4
= 70 * 16
After simplify this, we get
= 1120.
The 5th term of a geometric sequence is 1120.
The above examples are helpful to study of limit point of a sequence.
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